13 π 12 25) sin π 12 26) cos − 7π 12-2- - Read more

Sketch the regions enclosed by the given curves. y = 3 cos 6x, y = 3 sin 12x, x = 0, x = π/12 Find the area as well. 2. ... y = 3 cos 6x, y = 3 sin 12x, x = 0, x = π/12

... = sin A cos B + cos A sin B ... Find the exact value of cos 75 We can use the formulas to help us find ... sin70 sin20 sinπ 12 cos7 ...

Trig help to find exact value for tan(-π/12)? ok this has been bugging me all day, ... (√2+√6)/4. then i did sin(-π/12)/cos(-π/12) which came out to (√2-√6

... What is (cos 15) ^ 2 – (sin 15)^2, Topics: Math, Tags ... your questions get answered first by our expert eNotes Educators—teachers who will help you move to ...

I will be eternally grateful for the help provided. Thanks again. A)find sin 7π /12 B) ... (π /4) to find cos π /12 Answer by stanbon(64569) (Show Source):

... Find the exact value of sin π/12 and tan π/12 by ... Homework Help Find the exact value of sin π/12 and tan π/12 ... Substituting `sin pi/3,cos pi ...

given cos θ = 3/5, tan θ < 0 find: sin 2θ cos 2θ cot 2θ use half measure identities to find exact values of the following: tan 15 degrees sec π/12

... (π/12) sin(π/12)-cos(π/12)

pitanje Group Title. 6sin(π/12) cos(π/12) = 3(2 sin(π/12) cos(π/12) = 3sin (2) (π/12) = 3 sin (π/6) = 3 (1/2) =3/2 Why is 6 sin divided into 3sin (2) and what ...

13 π 12 25) sin π 12 26) cos ... 13 π 12 2 − 3 25) sin

... (π/12) = (1-cos(π/6))/sin(π/6), we get tan(π/12) = (1 - sqrt[{1+cos(π/3)}/2)/sqrt[{(1-cos(π/3)}/2]. Since the cos(π/3) is known to be √3/2,

Area = ∫ [0 to π/12] (6 cos 2x − 6 sin 4x) dx + ∫ [π/12 to π/4] (6 sin 4x − 6 cos 2x) dx..... = 3/4 + 3/4 ... Calculus help? Area between two curves?

1、-cos^2(π/12)+sin^2(π/12)=？（求值）2、(cos^210°-cos^280°）^2+cos^270°=？（化简）3、sin^4a+cos^4a+1/2sin^22a=？

... +sin²(π/12) =-[cos²(π/12)-sin²(π/12)] =-cos(2*π/12) =-cos(π/6) =-√3/2 ( 负2分之根号3) ... 3、sin^4a+cos^4a+1/2 sin²2a=(sin^4 a+cos^4 a+2sin² ...

sin(π/12)-cos(π/12)=-√(1/2)=-√2/2

π 12 Use the angle difference identity to find the exact value of each. 21) ... sin 15) tan 75° 17) cos 75° π 12 16) ... Help; FAQ; Press; Purchase help;

回答：1、-cos?(π/12)+sin?(π/12) =-[cos?(π/12)-sin?(π/12)] =-cos(2*π/12) =-cos(π/6) =-√3/2 ( 负2分之根号3) 2、(cos? 10°-cos? 80°）? +cos? 70° ...

... Use the Compound Angle Formulas to help ... triangle angles of π/6, π/3, π/4 and π/2. a) cos( π/12 ... sin (x + π) and cos (x + π/2 ) ...

cos2 x+sin2 x = 1 cos(u−v) = cosucosv +sinusinv sin(u+v) = sinucosv +cosusinv Any other formula I need I will derive from these. Questions ... π 12 = −2+ ...

已知cos(5π/12+α)=1/3，且-π＜α＜-π/2，则cos(π/12-α) ... (α+5π/12)，而cos(π/12-α)=cos[π/2-(5π/12+α)]=sin(5π/12+α)，从而可求解答 ...

I know that tan =sin/cos and 2√2 e^i(π/12) = 2√2[cos(π/12) ... I should be right from here thanks for tips, your help really helps!!.

... (kπ/6+π/12) = cos(kπ/6)cos(π/12) - sin(kπ/6)sin(π/12) 上述两式相减，得 2*sin(kπ/6)sin(π/12 ... cos(2k+1)π/12] =1/[2sin(π/12)] * 2*sin(kπ/6 ...

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sin(π/12)-√3 (cosπ/12) =2[sinπ/12cos60-sin60cosπ/12 =2sin ... sin（π/12）-(√3)cos（π/12）= =2[cos(π/3)sin(π/12)-sin(π/3)cos(π/12)] =2sin ... - Read more